разложим x² + 11x + 30 = (x+5)(x + 6)
D = 121 - 120 = 1
x12 = (-11 +- 1)/2 = -5 -6
lim(x->-5) (x² + 11x + 30)/(x² - 25) = lim(x->-5) (x + 5)(x + 6)/(x - 5)(x + 5) = lim(x->-5) (x + 6)/(x - 5) = (-5 + 6)/(-5 - 5) = - 1/10 = 1/(-10)
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разложим x² + 11x + 30 = (x+5)(x + 6)
D = 121 - 120 = 1
x12 = (-11 +- 1)/2 = -5 -6
lim(x->-5) (x² + 11x + 30)/(x² - 25) = lim(x->-5) (x + 5)(x + 6)/(x - 5)(x + 5) = lim(x->-5) (x + 6)/(x - 5) = (-5 + 6)/(-5 - 5) = - 1/10 = 1/(-10)