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metro2012
@metro2012
August 2022
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Вычислить массовую долю СЕРЫ в медном купоросе CuSO4 * 5H2O
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kurull235
Verified answer
W(S) = Ar(S)/Mr(CuSO4*5H2O) *100%
Mr(CuSO4*5H2O) = Mr(CuSO4) + 5*Mr(H2O) = 160+90 = 250
w(S) = 32/250 *100% = 12.8%
Ответ: w(S) = 12,8%
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Answers & Comments
Verified answer
W(S) = Ar(S)/Mr(CuSO4*5H2O) *100%Mr(CuSO4*5H2O) = Mr(CuSO4) + 5*Mr(H2O) = 160+90 = 250
w(S) = 32/250 *100% = 12.8%
Ответ: w(S) = 12,8%