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Konod
@Konod
August 2021
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вычислить массовую долю углерода в сахарозе C12H22O11
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gusmakvlad
Mr(C12H22O11)=12*12+1*22+16*11=144+22+176=342
W(C)=144/342*100%=42.1%
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Answers & Comments
W(C)=144/342*100%=42.1%