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queenxx
@queenxx
July 2022
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вычислить массу 0,3 моль сахарозы (С12Н22О11)
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IrVB
M = M*n
M(C12H22O11)=342 г/моль
m(C12H22O11) = 342*0,3 = 102,6 г
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Answers & Comments
M(C12H22O11)=342 г/моль
m(C12H22O11) = 342*0,3 = 102,6 г