Вычислить массу эфира, который образуется при взаимодействии 5 г. 90 % раствора этанола и 7 г. 9 % раствора уксусной кислоты в присутствии катализатора.
CH3CH2OH + CH3COOH = CH3COOCH2CH3 + H2O
m(CH3CH2OH) = 5*0.9 = 4.5 г
m(CH3COOH) = 7*009 = 0,63 г
n(CH3CH2OH) = m(CH3CH2OH)/M(CH3CH2OH) = 4.5/46 = 0.09782 моль
m(CH3COOH) = m(CH3COOH)/M(CH3COOH) = 0.63/60 = 0,0105 моль
CH3COOH - в недостатке
n(CH3COOCH2CH3) = n(CH3COOH) = 0.0105 моль
m(CH3COOCH2CH3) = n(CH3COOCH2CH3)*M(CH3COOCH2CH3) = 0.0105*88 = 0.924 г
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
CH3CH2OH + CH3COOH = CH3COOCH2CH3 + H2O
m(CH3CH2OH) = 5*0.9 = 4.5 г
m(CH3COOH) = 7*009 = 0,63 г
n(CH3CH2OH) = m(CH3CH2OH)/M(CH3CH2OH) = 4.5/46 = 0.09782 моль
m(CH3COOH) = m(CH3COOH)/M(CH3COOH) = 0.63/60 = 0,0105 моль
CH3COOH - в недостатке
n(CH3COOCH2CH3) = n(CH3COOH) = 0.0105 моль
m(CH3COOCH2CH3) = n(CH3COOCH2CH3)*M(CH3COOCH2CH3) = 0.0105*88 = 0.924 г