n(CH₄)=2000/(12+4*1)=125 моль
V = 125 * 22.4 = 2800 л
n(CH₄)=2000/(12+4*1)=125 моль 125 * 22.4 = 2800 л
вроде так
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Verified answer
n(CH₄)=2000/(12+4*1)=125 моль
V = 125 * 22.4 = 2800 л
n(CH₄)=2000/(12+4*1)=125 моль 125 * 22.4 = 2800 л
вроде так