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urasuper123
@urasuper123
July 2021
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вычислить объем водорода который можно добыть при взаимодействии 13 г цинка с серной кислотой
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axax68
Zn+H2SO4=ZnSO4+H2 n(Zn)=n(H2) n(Zn)=m/M n(Zn)=13/65=0.2 (моль) V(H2)=n*Vm V(H2)=0.2*22.4=4.48 (л)
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