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vikakirillova
@vikakirillova
June 2021
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вычислить объем водорода, выделившегося при взаимодействии 200 гр 10 % раствора HCl c Zn
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Alexandr26
Масса HCl=200*0,1=20
n(HCl)= 20/36,5=0,5
0,5/2=x/1
x=0,5/2=0,25
v(H2)=0,25*22,4=5,6 л
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Answers & Comments
n(HCl)= 20/36,5=0,5
0,5/2=x/1
x=0,5/2=0,25
v(H2)=0,25*22,4=5,6 л