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tiffany1
@tiffany1
June 2022
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вычислить представив аргумент в виде суммы или разности sin 135
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konik1
Sin (α + β) = sin α · cos β + cos α · sin β
sin (135) =
sin (90 + 45) = sin 90 · cos 45 + cos 90 · sin 45 = 1·√2/2 + 0
= √2/2
2 votes
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Answers & Comments
sin (135) = sin (90 + 45) = sin 90 · cos 45 + cos 90 · sin 45 = 1·√2/2 + 0 = √2/2