Ответ:
y'= (2/√(1+4x^2) - x/√(1+4x^2))/1+4x^2= 2-x/(√1+4x^2)(1+4x^2)
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Ответ:
y'= (2/√(1+4x^2) - x/√(1+4x^2))/1+4x^2= 2-x/(√1+4x^2)(1+4x^2)