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egorparamonov
@egorparamonov
November 2021
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hlopushinairina
(1/(3+√8))+(1/√8+√7))+(6/(√7-1)=
=(3-√8)/(3+√8)(3-√8))+(√8-√7)/(√8+√7)(√8-√7))+6·(√7+1)/(√7-1)(√7+1)=
=(3-√8)/(9-8)+(√8-√7)/(8-7)+6(√7+1)/(7-1)=
=(3-√8)/1+(√8-√7)/1+6(√7-1)/6=3-√8+√8-√7+√7-1=2
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Answers & Comments
=(3-√8)/(3+√8)(3-√8))+(√8-√7)/(√8+√7)(√8-√7))+6·(√7+1)/(√7-1)(√7+1)=
=(3-√8)/(9-8)+(√8-√7)/(8-7)+6(√7+1)/(7-1)=
=(3-√8)/1+(√8-√7)/1+6(√7-1)/6=3-√8+√8-√7+√7-1=2