11B(16)=11+1*16+1*16²=283(10)
10111111(2)=1+2+4+8+16+32+128=191(10)
117(8)=7+1*8+1*8²=79(10)
(283+191):79=6(10)
6(10)=4+2=110(2)
Ответ:110(2)
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11B(16)=11+1*16+1*16²=283(10)
10111111(2)=1+2+4+8+16+32+128=191(10)
117(8)=7+1*8+1*8²=79(10)
(283+191):79=6(10)
6(10)=4+2=110(2)
Ответ:110(2)