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юлия1520
@юлия1520
July 2022
2
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вычислите: 81а²+18a+1 при а=одна целая одна третия:
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kørøłeBã
,при а=1 1/3
81*1 1/3^2 +18*1 1/3+1=81*16/9+18*4/3+1=144+24+1=169
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kørøłeBã
/ - это дробная чарта а это ^- степень
wangross
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81*1 1/3^2 +18*1 1/3+1=81*16/9+18*4/3+1=144+24+1=169