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Magomed8272
@Magomed8272
August 2022
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вычислите f(x)=0
f(x)=6x^2+32x+2008
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ПрофиЗнания
F'(x)=12x+32+0=12x+32
f'(x)=0
12x+32=0
12x=-32
x=-32/12
x=-8/3
x=-2 2/3
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Answers & Comments
f'(x)=0
12x+32=0
12x=-32
x=-32/12
x=-8/3
x=-2 2/3