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Fyyf5001
@Fyyf5001
July 2022
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Вычислите. И напишите решение, пожалуйста.
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uekmyfhfp
= 2^(3/2) *2^(-1/2) *3^(-1/2)
/
(3^2)^(-1/6) *3^(5/6) =
= 2^(3/2 -1/2) *3^(-1/2)
/ (
3^(2*(-1/6)) *3^(5/6)
)
=2*3^(-1/2)/
(
3^(-2/6+5/6)
) =
=2*1/
(
3^(1/2)*3^(1/2)
) =2/3 .
0 votes
Thanks 0
Fyyf5001
не верно. во-первых, с какой стати множители меняются местами?
во-вторых 3^(-1) = 1/3
oganesbagoyan
Все правильно, кроме 2 * 3^(-1) =2* 3^1 = 2*3 = 6 ? 2 * 3^(-1) =2*(1/3)
oganesbagoyan
Это элементарное упущение, никак _ ошибка
oganesbagoyan
Verified answer
= (2^3/2 * 9^1/6) /(6^1/2* 3^5/6) = (2^3/2 * 3^2/6) / (2^1/2 * 3^1/2 * 3^5/6) =
= 2^(3/2 - 1/2) * 3^( 2/6 - 1/2 - 5/6) = 2^1 * 3^( 2/6 - 3/6 - 5/6) = 2 * 3^(-1) =
=2* 3^1 = 2*3 = 6
2 votes
Thanks 1
Fyyf5001
в конце не так, у меня ответ 1/6
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Answers & Comments
= 2^(3/2 -1/2) *3^(-1/2) / ( 3^(2*(-1/6)) *3^(5/6) ) =2*3^(-1/2)/(3^(-2/6+5/6)) =
=2*1/( 3^(1/2)*3^(1/2)) =2/3 .
во-вторых 3^(-1) = 1/3
Verified answer
= (2^3/2 * 9^1/6) /(6^1/2* 3^5/6) = (2^3/2 * 3^2/6) / (2^1/2 * 3^1/2 * 3^5/6) == 2^(3/2 - 1/2) * 3^( 2/6 - 1/2 - 5/6) = 2^1 * 3^( 2/6 - 3/6 - 5/6) = 2 * 3^(-1) =
=2* 3^1 = 2*3 = 6