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adya1
@adya1
July 2022
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вычислите интеграл от -1 до 1 ((6x-22)dx
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| - ЗНАЧОК ИНТЕГРАЛА
|(6x-22)dx=6|xdx-22|dx=(6*x^2\2)-22x=3x^2-22x=(3*1^2-3*(-1)^2)-(22*1-22*(-1)=0-44=-44
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| - ЗНАЧОК ИНТЕГРАЛА|(6x-22)dx=6|xdx-22|dx=(6*x^2\2)-22x=3x^2-22x=(3*1^2-3*(-1)^2)-(22*1-22*(-1)=0-44=-44