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anderssson
@anderssson
August 2022
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Вычислитe концентрацию ионов Н+ и pH 0.1 н. раствора NH4Cl, если константа диссоциации NH4OH равна 1,8·10-5.
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Виктория0503
Verified answer
PH = -lg[H+]
0.1 = 10^(-1)
[OH-] = √Kд*С = √1.8*10^(-5)*10^(-1) = √1.8*10^(-6) = 1.34*10^(-3)
[Н+] = Кв/[ОН-] = 10^(-14)/1.34*10^(-3) 0.75*10^(-11)
рН = -lg 0.75*10^(-11) = 11 - 0.12 = 10.88
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Answers & Comments
Verified answer
PH = -lg[H+]0.1 = 10^(-1)
[OH-] = √Kд*С = √1.8*10^(-5)*10^(-1) = √1.8*10^(-6) = 1.34*10^(-3)
[Н+] = Кв/[ОН-] = 10^(-14)/1.34*10^(-3) 0.75*10^(-11)
рН = -lg 0.75*10^(-11) = 11 - 0.12 = 10.88