Home
О нас
Products
Services
Регистрация
Войти
Поиск
alina28042002
@alina28042002
August 2022
2
7
Report
вычислите массовую долю элемента кислород: а) в воде; б) в кварце SiO2; в) в серной кислотеH2SO4; г) в соде Na2CO3.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Alexei78
Verified answer
A) H2O
M(H2O)=18 g/mol
Ar(O)=16
W(O)=Ar / Mr * 100% = 16 / 18*100%=88.89%
б) SiO2
M(SiO2)=28*16*2=60 g/mol
W(O) = 16*2 / 60*100%=53.33 %
в) H2SO4
M(H2SO4)=98 g/mol
W(O)=16*4 / 98*100%=65.3%
г) Na2CO3
M(Na2CO3)=23*2+12+16*3=106 g/mol
W(O)=16*3 / 106*100%= 45.3%
1 votes
Thanks 1
JeTime
Verified answer
A)Mr ( H2O) = (1*2) + 16 = 18
W (O) = 16/18 * 100% = 88.8 ~ 89%
б)Mr (SiO2) = 28 + (16*2) = 60
W(O) = 32/60 * 100% = 53.3%
в)Mr ( H2SO4) = (1*2) + 32 + (16*4) = 98
W(O) = 64 / 98 * 100% = 65.3%
г)Mr (Na2CO3) = (23 * 2) + 12 + (16 * 3) = 106
W (O) = 48 / 106 * 100% = 45.2%
1 votes
Thanks 0
More Questions From This User
See All
alina28042002
August 2022 | 0 Ответы
sostavte uravneniya reakcij podtverzhdayushih harakter oksidov i gidroksidov akal2c3345a54255b2f96df7df44e38ab5db 48179
Answer
alina28042002
August 2022 | 0 Ответы
pomogite s etimi dvumya zadaniyami6f0ac983d95db8e35fb5c79d79fc40f6 78484
Answer
alina28042002
August 2022 | 0 Ответы
pomogite pozhalujsta53b6d57ed3eda9c9275df0f1513de7d4 54691
Answer
alina28042002
August 2022 | 0 Ответы
vychislite massu vodoroda poluchennogo a razlozheniem 126g vody brazlozheniem me
Answer
alina28042002
August 2022 | 0 Ответы
pozhalujstaaaaaaaa69ecdfe6d379129065cd0a58c3d216e1 15878
Answer
alina28042002
August 2022 | 0 Ответы
pomogite pozhalujsta768eb5b143831450238548fd1abdaa66 19423
Answer
alina28042002
August 2022 | 0 Ответы
kakuyu massu kisloroda mozhno poluchit pri razlozhenii a 180g vody b 17g peroksi
Answer
alina28042002
August 2022 | 0 Ответы
najdite massy oksidov produkty reakcii okisleniya esli kolichestvo ishodnyh vesh
Answer
alina28042002
August 2022 | 0 Ответы
eti dva zadaniya pozhalujsta879fc73ed3f8f599fa743035fb3193c4 72905
Answer
alina28042002
August 2022 | 0 Ответы
na skolko sutok cheloveku hvatit 54 m kubicheskih vozduha esli v chas cheloveku tr
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "вычислите массовую долю элемента кислород: а) в воде; б) в кварце SiO2; в) в сер..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
A) H2OM(H2O)=18 g/mol
Ar(O)=16
W(O)=Ar / Mr * 100% = 16 / 18*100%=88.89%
б) SiO2
M(SiO2)=28*16*2=60 g/mol
W(O) = 16*2 / 60*100%=53.33 %
в) H2SO4
M(H2SO4)=98 g/mol
W(O)=16*4 / 98*100%=65.3%
г) Na2CO3
M(Na2CO3)=23*2+12+16*3=106 g/mol
W(O)=16*3 / 106*100%= 45.3%
Verified answer
A)Mr ( H2O) = (1*2) + 16 = 18W (O) = 16/18 * 100% = 88.8 ~ 89%
б)Mr (SiO2) = 28 + (16*2) = 60
W(O) = 32/60 * 100% = 53.3%
в)Mr ( H2SO4) = (1*2) + 32 + (16*4) = 98
W(O) = 64 / 98 * 100% = 65.3%
г)Mr (Na2CO3) = (23 * 2) + 12 + (16 * 3) = 106
W (O) = 48 / 106 * 100% = 45.2%