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manihinatatyan
@manihinatatyan
November 2021
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вычислите массовую долю кислорода в веществе NaOH
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lyubavasil
W=n*Ar*100%/Mr Ar(O)=16 Mr(NaOH)=23+16+1=40
W(O)= 1*16*100/40=40%
Ответ:40%
8 votes
Thanks 19
rajab0v007
Масса NaOH- будет 30
0 votes
Thanks 0
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Answers & Comments
W(O)= 1*16*100/40=40%
Ответ:40%