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dilari14
@dilari14
August 2022
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Вычислите массовую долю водорода в фосфорной кислоте H3PO4.
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krioira
Verified answer
Mr(H3PO4)=3*1+31+4*16=98
W(H)=3/98=0.03=3%
3 votes
Thanks 1
dilari14
А как записать дано?
krioira
Дано: H3PO4 Найти: W(H)=?
Alexei78
Verified answer
Дано
H3PO4
--------------
W(H)-?
M(H3PO4)=1*3+31+16*4=98 g/mol
W(H)=1*3/98*100%=3.06%
ответ 3.06%
4 votes
Thanks 4
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Answers & Comments
Verified answer
Mr(H3PO4)=3*1+31+4*16=98W(H)=3/98=0.03=3%
Verified answer
ДаноH3PO4
--------------
W(H)-?
M(H3PO4)=1*3+31+16*4=98 g/mol
W(H)=1*3/98*100%=3.06%
ответ 3.06%