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aleksandramaty1
@aleksandramaty1
July 2022
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вычислите массовые доли элемента PbCO3
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nazipov
Mr(PbCO3)=207+12+3*16=267
ω(Pb)=207/267=0,7753 или 77,53
ω(C)=12/267=0,0449 или 4,49
ω(O)=48/267=0,1798 или 17,98
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Answers & Comments
ω(Pb)=207/267=0,7753 или 77,53
ω(C)=12/267=0,0449 или 4,49
ω(O)=48/267=0,1798 или 17,98