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copatch
@copatch
July 2022
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Вычислите массовые доли элементов в азотной кислоте HNO3
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SeaWorld
1. Находим молярную массу HNO3=1*1+1*14+3*116=63
W(H)=(1/63)*100%=1,6%
W(N)=(14/63)*100%=22,2%
W(0)=(3*16/63)*100%=76,2%
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Answers & Comments
W(H)=(1/63)*100%=1,6%
W(N)=(14/63)*100%=22,2%
W(0)=(3*16/63)*100%=76,2%