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МадиярMLG
@МадиярMLG
August 2021
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Вычислите массовые доли элементов в веществе Ag2O
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dec77cat
Verified answer
Ag₂O
w(Ag)=2M(Ag)/M(Ag₂O)
w(Ag)=2*108/232=0,931
w(O)=1-w(Ag)
w(O)=1-0,931=0,069
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Answers & Comments
Verified answer
Ag₂Ow(Ag)=2M(Ag)/M(Ag₂O)
w(Ag)=2*108/232=0,931
w(O)=1-w(Ag)
w(O)=1-0,931=0,069