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berezhnayaoksap2ekjk
@berezhnayaoksap2ekjk
July 2022
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Вычислите массу и число молекул 5,6 л у оксида азота (5)
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ХимикL
N(N2O5)= V/Vm= 5.6/22.4=0.25 моль.
m(N2O5)= n*M= 0.25*108=27г
N= n* NA= 0.25* 6.02*10^23= 1.505*10^23
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Answers & Comments
m(N2O5)= n*M= 0.25*108=27г
N= n* NA= 0.25* 6.02*10^23= 1.505*10^23