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nataxa71
@nataxa71
July 2022
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вычислите массу кислорода необходимого для полного сжигания 78 г калия
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mrvladimir2
Verified answer
78 г х г
4K + O2 = 2K2O
156 г 32 г
78:156=х:32
х=16 г
0 votes
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Answers & Comments
Verified answer
78 г х г4K + O2 = 2K2O
156 г 32 г
78:156=х:32
х=16 г