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valeriamakeevaozb22e
@valeriamakeevaozb22e
August 2022
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вычислите массу оксида алюминия который образовался при взаимодействии 2,7 гр алюминия с кислородом
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pomogayka01
2.7г x
4Al+3O2=2Al2O3
v=4 v=2
M=27 M=102
v(Al)=2.7/27=0.1
v(Al2O3)=0.05
m(Al2O3)=5.1г
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Answers & Comments
4Al+3O2=2Al2O3
v=4 v=2
M=27 M=102
v(Al)=2.7/27=0.1
v(Al2O3)=0.05
m(Al2O3)=5.1г