H2SO4+BaCl2=BaSO4+2HCl
9.8*233/98=23.3
23.3 г BaSO4
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H2SO4+BaCl2=BaSO4+2HCl
9.8*233/98=23.3
23.3 г BaSO4
m(BaCl2)=50 г m(BaSO4)0,1*258=25,8 г
n(H2SO4)=9,8:98=0,1 моль
m(BaSO4)-?