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polonskaangelina
@polonskaangelina
August 2022
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Вычислите массу соли, которая образуется при взаимодействии NaOH массой 16 г и CO2 массой 4,2 г.
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svetlanavpopk
2NaOH+CO2=Na2CO3+H2O
nNaOH=16/Mr(40)=0,4
nCO2=4,4/44=0,1 моль
2:1=0,4:0,1
Решаем по недостатку 0,1<0,4
nNa2CO3=1/2nCO2=0,1/2=0,05 по уравнению
mNa2CO3=0,05*Mr(46+12+48=106)=5,3г масса соли
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polonskaangelina
Спасибо большое^^
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Answers & Comments
nNaOH=16/Mr(40)=0,4
nCO2=4,4/44=0,1 моль
2:1=0,4:0,1
Решаем по недостатку 0,1<0,4
nNa2CO3=1/2nCO2=0,1/2=0,05 по уравнению
mNa2CO3=0,05*Mr(46+12+48=106)=5,3г масса соли