Zn + 2HCl = ZnCl2 + H2
1)n(ZnCl2) = 2(HCl) = 0,5*2 = 1 моль
2)m(HCl) = mr*n = 36,5 г
3)m(HCl раствор) = m/0,2 = 182,5 г
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Zn + 2HCl = ZnCl2 + H2
1)n(ZnCl2) = 2(HCl) = 0,5*2 = 1 моль
2)m(HCl) = mr*n = 36,5 г
3)m(HCl раствор) = m/0,2 = 182,5 г