∫((sinx)-5x)dx=-cosx-5x²/2+c
(-cosx-5x²/2+c)'=-(-sinx)-2*x*5/2+0=(sinx)-5x
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∫((sinx)-5x)dx=-cosx-5x²/2+c
(-cosx-5x²/2+c)'=-(-sinx)-2*x*5/2+0=(sinx)-5x