1) 237 = 1·3·79; 215 = 1·5·43.
НОД(237, 215) = 1
НОК(237, 215) = 3·79·5·43 = 237·215 = 237·(200+10+5) = 47 400 + 2 370 + 1 185 = 50 955
2) 1998 = 2·9·37 = 2·3²·37; 111 = 3·37.
НОД(1998, 111) = 3·37 = 111
НОК(1998, 111) = 2·3²·37 = 1998
3) 25 = 1·5²; 27 = 1·3³
НОД(25; 27) = 1
НОК(25, 27) = 5²·3³ = 25·27 = 25·(20+7) = 500+175 = 675
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Verified answer
1) 237 = 1·3·79; 215 = 1·5·43.
НОД(237, 215) = 1
НОК(237, 215) = 3·79·5·43 = 237·215 = 237·(200+10+5) = 47 400 + 2 370 + 1 185 = 50 955
2) 1998 = 2·9·37 = 2·3²·37; 111 = 3·37.
НОД(1998, 111) = 3·37 = 111
НОК(1998, 111) = 2·3²·37 = 1998
3) 25 = 1·5²; 27 = 1·3³
НОД(25; 27) = 1
НОК(25, 27) = 5²·3³ = 25·27 = 25·(20+7) = 500+175 = 675