Zn+2HCl=ZnCl2+H2
m(Zn)=100*0.13=13грамм; n(Zn)=13/65=0.2моль
V(H2)=0.2*22.4=4.48литра
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Zn+2HCl=ZnCl2+H2
m(Zn)=100*0.13=13грамм; n(Zn)=13/65=0.2моль
V(H2)=0.2*22.4=4.48литра