Ответ:
дано
m(HCL) = 25.55 g
η(H2) = 70%
------------------------
V пр (H2)-?
Mg+2HCL-->MgCL2+H2
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 25.55 / 36.5 = 0.7 mol
2n(HCL) = n(H2)
n(H2) = 0.7 * 1 / 2 = 0.35 mol
Vтеор(H2) = n*Vm = 0.35 * 22.4 = 7.84 L
V пр(H2) = 7.84 * 70% / 100% = 5.488 L
ответ 5.488 л
Объяснение:
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Answers & Comments
Ответ:
дано
m(HCL) = 25.55 g
η(H2) = 70%
------------------------
V пр (H2)-?
Mg+2HCL-->MgCL2+H2
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 25.55 / 36.5 = 0.7 mol
2n(HCL) = n(H2)
n(H2) = 0.7 * 1 / 2 = 0.35 mol
Vтеор(H2) = n*Vm = 0.35 * 22.4 = 7.84 L
V пр(H2) = 7.84 * 70% / 100% = 5.488 L
ответ 5.488 л
Объяснение: