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katiailina200
@katiailina200
July 2022
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вычислите объем воздуха который потребуется для сжигания 30 г этена
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Alexei78
30 X L
С2H4+4O2-->2CO2+4H2O M(C2H4)=28 g/mol Vm=22.4L/mol
28 4*22.4
30 /28 = X/89.6
X=96 л - кислорода
V(возд)=96*100%/21%=457.14 л
ответ 457.14 л
3 votes
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Answers & Comments
С2H4+4O2-->2CO2+4H2O M(C2H4)=28 g/mol Vm=22.4L/mol
28 4*22.4
30 /28 = X/89.6
X=96 л - кислорода
V(возд)=96*100%/21%=457.14 л
ответ 457.14 л