дано
V(H2S) = 20 m3
----------------------
V(возд)-?
m(возд)-?
2H2S+3O2-->2H2O+2SO2
n(H2S) = V(H2S) / Vm = 20 / 22.4 = 0.89 kmol
2n(H2S) = 3n(O2)
n(O2) = 3*0.89 / 2 = 1.335 kmol
V(O2) = n*Vm =1.335 * 22.4 = 29.904 m3
V(возд) = 29.904 * 100% / 21% = 142.4 m3
M(возд) = 29 kg/kmol
m(возд) = M(возд) * V(возд) / Vm = 29*142.4 / 22.4 = 184.36 kg
ответ 142.4 м3, 184.36 kg
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Verified answer
дано
V(H2S) = 20 m3
----------------------
V(возд)-?
m(возд)-?
2H2S+3O2-->2H2O+2SO2
n(H2S) = V(H2S) / Vm = 20 / 22.4 = 0.89 kmol
2n(H2S) = 3n(O2)
n(O2) = 3*0.89 / 2 = 1.335 kmol
V(O2) = n*Vm =1.335 * 22.4 = 29.904 m3
V(возд) = 29.904 * 100% / 21% = 142.4 m3
M(возд) = 29 kg/kmol
m(возд) = M(возд) * V(возд) / Vm = 29*142.4 / 22.4 = 184.36 kg
ответ 142.4 м3, 184.36 kg