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ParaDoks21
@ParaDoks21
July 2022
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Вычислите определённые интегралы, нужен только пункт б
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sharadi
Verified answer
₂∫³ ( 8x³ - 12x² + 6x -1)dx = (8x⁴/4 - 12x³/3 + 6x²/2 - x)| в пределах от 2 до 3 =
= (2х⁴ - 4х³ + 3х² - х) | в пределах от 2 до 3 =
=(2*81 - 4*27 +3*9 -3)- ( 2*16 -4*8 +3*4 -2) =
= 162 - 108 +27 -3 -32 +32 -12 +2 = 68
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Answers & Comments
Verified answer
₂∫³ ( 8x³ - 12x² + 6x -1)dx = (8x⁴/4 - 12x³/3 + 6x²/2 - x)| в пределах от 2 до 3 == (2х⁴ - 4х³ + 3х² - х) | в пределах от 2 до 3 =
=(2*81 - 4*27 +3*9 -3)- ( 2*16 -4*8 +3*4 -2) =
= 162 - 108 +27 -3 -32 +32 -12 +2 = 68