Ответ:
Mr(C₁₂H₂₂O₁₁) = 12×12 + 22×1 + 11×16 = 144 + 22 + 176 = 342 а.е.м.
ω(C) = 144/342 × 100% = 42,10%
ω(H) = 22/342 × 100% = 6,43%
ω(O) = 100% - 42,10% - 6,43% = 51,47%
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Ответ:
Mr(C₁₂H₂₂O₁₁) = 12×12 + 22×1 + 11×16 = 144 + 22 + 176 = 342 а.е.м.
ω(C) = 144/342 × 100% = 42,10%
ω(H) = 22/342 × 100% = 6,43%
ω(O) = 100% - 42,10% - 6,43% = 51,47%