∠C=135° т.к. AB=CD;
∠A=∠D=135°-90°=45°;
MD=12
AD=12+12+10=34
S=((BC+AD)/2) *12=((10+34)/2) *12=22*12=264
Ответ:264
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∠C=135° т.к. AB=CD;
∠A=∠D=135°-90°=45°;
MD=12
AD=12+12+10=34
S=((BC+AD)/2) *12=((10+34)/2) *12=22*12=264
Ответ:264