Ответ: S=4,5 кв. ед.
Объяснение:
y=x²+1 y=x+3 S=?
x²+1=x+3
x²-x-2=0 D=9 √D=3
x₁=-1 x₂=2 ⇒
S=₋₁∫²(x+3-(x²+1))dx=₋₁∫²(x+3-x²-1)dx=₋₁∫²(2+x-x²)dx=(2x+(x²/2)-x³/3) ₋₁|²=
=(2*2+2²/2-2³/3)-(2*(-1)+(-1)²/2-(-1)³/3)=4+2-8/3-(-2+(1/2)+(1/3))=
=6-8/3+1,5-1/3=7,5-(9/3)=7,5-3=4,5.
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Ответ: S=4,5 кв. ед.
Объяснение:
y=x²+1 y=x+3 S=?
x²+1=x+3
x²-x-2=0 D=9 √D=3
x₁=-1 x₂=2 ⇒
S=₋₁∫²(x+3-(x²+1))dx=₋₁∫²(x+3-x²-1)dx=₋₁∫²(2+x-x²)dx=(2x+(x²/2)-x³/3) ₋₁|²=
=(2*2+2²/2-2³/3)-(2*(-1)+(-1)²/2-(-1)³/3)=4+2-8/3-(-2+(1/2)+(1/3))=
=6-8/3+1,5-1/3=7,5-(9/3)=7,5-3=4,5.