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robbigfirli
@robbigfirli
June 2022
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вычислите площадь фигуры, ограниченной осью абцисс и параболой:
1)y=x^2, 2x+y-3=0
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3X^2 - 2X = 3X - 2 3X^2 - 5X + 2 = 0 D = 25 - 24 = 1 √ D = 1 X1 = ( 5 + 1 ) : 6 = 1 X2 = ( 5 - 1 ) : 6 = 2/3 Y = 3X - 2 Y1 = 3 * 1 - 2 = 1 Y2 = 3 * ( 2/3 ) - 2 = 0 Ответ ( 1 ; 1 ) ; ( 2/3 ; 0 )
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