S=∫²₀(1,5x+1-2ˣ)dx=
=(1,5·(x²/2)+x-(2ˣ/ln2))|²₀=1,5·(2²/2)+2-(2²/ln2)-1,5·(0²/2)-0+(2⁰/ln2)=
=3+2-(3/ln2)=5-(3/ln2)
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S=∫²₀(1,5x+1-2ˣ)dx=
=(1,5·(x²/2)+x-(2ˣ/ln2))|²₀=1,5·(2²/2)+2-(2²/ln2)-1,5·(0²/2)-0+(2⁰/ln2)=
=3+2-(3/ln2)=5-(3/ln2)