1)Sф=S1+S2+S3
S1=a×b
S1=(4+1)×4=20
2)S2=a×a
S2=1×1=1
3)S3=a×b
S3=(3+1)×2=8
4)Sф=20+1+8=29
Ответ:29
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1)Sф=S1+S2+S3
S1=a×b
S1=(4+1)×4=20
2)S2=a×a
S2=1×1=1
3)S3=a×b
S3=(3+1)×2=8
4)Sф=20+1+8=29
Ответ:29