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Азяка21
@Азяка21
July 2022
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Вычислите, пожалуйста : cos0°+sin^2 45°-sin120°*cos210°+ctg(-90°)
ответ должен быть 2.25
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Verified answer
Cos0° + Sin²45° - Sin120°* Cos210° + ctg(-90°) = 1 +(1/√2)² - Sin(90° + 30°)*Cos(180° + 30°) - ctg90° = 1 + 0,5 - Cos30° * (- Cos30°) - 0 = 1,5 +
+ √3/2 * √3/2 = 1,5 +3/4 = 1,5 + 0,75 = 2,25
3 votes
Thanks 3
Азяка21
огромное спасибо! а вот эти сможешь? https://znanija.com/task/26406706
Азяка21
https://znanija.com/task/26406716
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Verified answer
Cos0° + Sin²45° - Sin120°* Cos210° + ctg(-90°) = 1 +(1/√2)² - Sin(90° + 30°)*Cos(180° + 30°) - ctg90° = 1 + 0,5 - Cos30° * (- Cos30°) - 0 = 1,5 ++ √3/2 * √3/2 = 1,5 +3/4 = 1,5 + 0,75 = 2,25