вычислите следующий пример
cos72=cos(90-18)=sin18
cos(105-5)/cos(18+62) = cos100/cos80 = cos(180-80)/cos80 = -cos80/cos80 = -1
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cos72=cos(90-18)=sin18
cos(105-5)/cos(18+62) = cos100/cos80 = cos(180-80)/cos80 = -cos80/cos80 = -1