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monstermor
@monstermor
July 2022
1
13
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Вычислите сумма двух членов арифметической прогрессии, если а10 = -32, а d = -3.
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Kalimbet
А10=а1+9d
-32=a1+9*(-3)
отсюда а1= -5
S2=a1+a2=a1+a1+d= -5 + (-5) + (-3)= -13
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Answers & Comments
-32=a1+9*(-3)
отсюда а1= -5
S2=a1+a2=a1+a1+d= -5 + (-5) + (-3)= -13