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romanersisyan
@romanersisyan
June 2021
2
8
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выписано несколько последовательных членов арифметической прогрессии:-126,-123...Найдите номера члена этой прогрессии,равного -99
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SAdsdaASDAFDSADF
-126 , -123 , -120, -117,-114, -111,-108 , -105, - 102 , -99
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BronyPonyMew
A1=-126
a2= -123
an= -99
n - ?
an=a1+d×(n-1)
-123=-126+d×(2-1)
-126+d=-123
d=-123+126
d=3
-99=-126+3×(n-1)
-126+3n-3=-99
3n=30
n=10
Ответ: 10
0 votes
Thanks 0
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Answers & Comments
a2= -123
an= -99
n - ?
an=a1+d×(n-1)
-123=-126+d×(2-1)
-126+d=-123
d=-123+126
d=3
-99=-126+3×(n-1)
-126+3n-3=-99
3n=30
n=10
Ответ: 10