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thvfrjdf1999
@thvfrjdf1999
August 2022
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Выписаны первые несколько членов арифметической прогрессии: − 3; 1;
5; … Найдите сумму первых шестидесяти её членов.
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sova761
S61=(2·a1+d(n-1))·n/2
d=1-(-3)=4.
S=(2·(-3)+4·60)·61/2=7137
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Answers & Comments
d=1-(-3)=4.
S=(2·(-3)+4·60)·61/2=7137