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0Toni0
@0Toni0
March 2022
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Выписаны первые несколько членов геометрической порогрессии:7;-35;175.. Найдите сумму первых ее четырехчленов
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ShirokovP
Verified answer
B1 = 7
b2 = - 35
q = b2/b1 = - 5
S4 = b1*(1 - q^4)/(1 - q) = 7*(-624)/6 = - 728
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Answers & Comments
Verified answer
B1 = 7b2 = - 35
q = b2/b1 = - 5
S4 = b1*(1 - q^4)/(1 - q) = 7*(-624)/6 = - 728