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Anutka2010
@Anutka2010
April 2021
2
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Выписаны первые несколько членов геометрической прогрессии: 1; -5; 25; ... Найдите сумму первых 5 её членов
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sergeysotnikov
D=a2-a1=>-5-1=-6
S5=(2*(1)-6(5-1)*5)/2=-55
4 votes
Thanks 4
AlenaMolnar
Q= -5\1= -5 S5=b1*(q^n-1)\1-q=1*((-5)^5-1)\1+5=-3126\6=-521
7 votes
Thanks 3
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Answers & Comments
S5=(2*(1)-6(5-1)*5)/2=-55