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Алприка
@Алприка
July 2022
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выполни умножение: (d−2)(10d+1)(4d−10)
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tatsach
(d−2)(10d+1)=10d²+d-20d-2=10d²-19d-2
(10d²-19d-2)(4d-10)=40d³-100d²-76d²+190d-8d+20=40d³-176d²+181d+20
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Answers & Comments
(10d²-19d-2)(4d-10)=40d³-100d²-76d²+190d-8d+20=40d³-176d²+181d+20